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Grade 10 CAPS: measures of central tendency for ungrouped and grouped data, quartiles, the five-number summary, and the box-and-whisker diagram — the toolkit every later grade builds on.

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Grade 10 CAPS Mathematics

Statistics

How to summarise a set of data with a single typical value, and how spread-out it really is. Every worked example below moves from a direct calculation up to a genuine application, so work through them in order.

The 3-Year Statistics Journey

Grade 10 builds the summary toolkit every later grade extends.

10
Build

Central tendency • grouped data • quartiles • box & whisker

11
Extend

Histograms • ogives • variance & standard deviation • outliers

12
Apply

Bivariate data • scatter plots • regression & correlation

Study rule
Statistics is not really about the formulas — it's about choosing the RIGHT summary for the data in front of you, and then saying something true about it. Every slide below ends with "so what does this tell us?"

What CAPS Actually Asks in Grade 10

Two weeks, five connected skills, all about describing ONE set of data.

  • 1

    Revise measures of central tendency (mean, median, mode) in ungrouped data.

  • 2

    Measures of central tendency in grouped data: calculate an estimate of the mean, and identify the modal interval and the interval in which the median lies.

  • 3

    Revise range as a measure of dispersion, extended to include percentiles, quartiles, the interquartile range and the semi-interquartile range.

  • 4

    Five-number summary (minimum, quartiles, maximum) and the box-and-whisker diagram.

  • 5

    Use these statistical summaries and graphs to analyse and make meaningful comments on the context of the data.

Not yet
Histograms, frequency polygons, ogives, variance and standard deviation are Grade 11 content. Grade 10 stops at the five-number summary and the box-and-whisker diagram.

What Kind of Data Is It?

Before summarising any data set, know what TYPE of data you're holding.

Qualitative

Described in words, not numbers — e.g. favourite subjects, eye colours. Cannot be added, averaged, or put on a number line. Splits further into CATEGORICAL (a limited, fixed set of options, e.g. sandwich fillings chosen from a list) and ANECDOTAL (open-ended, story-form answers with no fixed set of options, e.g. "describe your dream job").

Quantitative — discrete

Numerical and COUNTED, so it only takes whole-number values — e.g. number of siblings, number of cars in a parking lot.

Quantitative — continuous

Numerical and MEASURED, so it can take any value in a range, including decimals — e.g. height, mass, time.

Worked example — classify three data sets Level 1

Classify each data set: (a) \(\{23; 25; 22; 26; 27\}\), sweets counted in a packet. (b) \(\{\text{"cheese"; "jam"; "honey"; "cheese"}\}\), sandwich fillings learners chose. (c) \(\{1{,}70\text{ m}; 1{,}41\text{ m}; 1{,}60\text{ m}; 1{,}32\text{ m}\}\), heights of learners.

Show solution
  1. 1(a) These are numbers, and since you can only ever COUNT a whole sweet (never "22,5 sweets"), this is \(\boxed{\text{quantitative discrete}}\)
  2. 2(b) These are words, not numbers, so this is \(\boxed{\text{qualitative}}\)
  3. 3(c) These are numbers, and height is MEASURED (it can genuinely take any decimal value, e.g. 1,703 m), so this is \(\boxed{\text{quantitative continuous}}\)
Why this matters
Mean, median and standard deviation only ever make sense for QUANTITATIVE data. For qualitative data, the mode is the only measure of central tendency that still applies — you can find the most common eye colour, but you cannot "average" eye colours.

Central Tendency — A Quick Revision

Three different "typical" values, each with its own use.

Mean (\(\bar{x}\))

Add every value, divide by how many there are. Uses every single value — but one extreme outlier can drag it a long way from the "typical" value.

Median

Arrange the data in order; the middle value (or the average of the two middle values, if there is an even number of values). Barely affected by an outlier.

Mode

The value that occurs most often. The only measure that also makes sense for non-numerical (categorical) data.

Why this choice matters
A property developer advertising "average house price R2,4 million" in a street of nine R1,8 million homes and one R10 million mansion is technically using the mean correctly — but the median (R1,8 million) is the far more honest "typical" price. Always ask whether an outlier is pulling the mean away from what's typical.

Worked Examples — Ungrouped Data

Straight from a raw list of values.

Worked example — odd number of values Level 1

Find the mean, median and mode of: \(7,\ 9,\ 4,\ 15,\ 7,\ 12,\ 10\)

Show solution
  1. 1Mean: add all 7 values and divide by 7: \(\dfrac{4+7+7+9+10+12+15}{7}=\dfrac{64}{7}\approx9{,}14\)
  2. 2Median: arrange in order — \(4,7,7,9,10,12,15\) — with 7 values, the middle (4th) value is the median: \(\boxed{9}\)
  3. 3Mode: \(7\) appears twice, every other value appears once: \(\boxed{\text{mode}=7}\)
  4. 4\(\boxed{\bar{x}\approx9{,}14,\ \text{median}=9,\ \text{mode}=7}\)
Worked example — even number of values Level 2

Find the mean and median of: \(20,\ 15,\ 30,\ 12,\ 25,\ 18,\ 22,\ 28\)

Show solution
  1. 1Mean: \(\dfrac{12+15+18+20+22+25+28+30}{8}=\dfrac{170}{8}=21{,}25\)
  2. 2Median: arrange in order — \(12,15,18,20,22,25,28,30\) — with 8 values (even), average the two middle values (4th and 5th): \(\dfrac{20+22}{2}=21\)
  3. 3\(\boxed{\bar{x}=21{,}25,\ \text{median}=21}\) — note the mean and median are close here, since this data set has no extreme outlier
Worked example — find the missing value Level 3

The mean of 5 numbers is 12. Four of the numbers are \(8,\ 10,\ 14,\ 16\). Find the fifth number.

Show solution
  1. 1Work backward from the mean formula: if the mean of 5 numbers is 12, their TOTAL must be \(5\times12=60\)
  2. 2The four known numbers add up to \(8+10+14+16=48\)
  3. 3The fifth number makes up the difference: \(60-48=\boxed{12}\)
  4. 4Check: mean of \(8,10,14,16,12\) is \(\dfrac{60}{5}=12\)✓
Recognise it when...
"Find the missing value" questions are really just the mean formula solved backward: \(\text{total}=\text{mean}\times n\). Find the total first, then subtract what you already know.
Worked example — organising raw data with a stem-and-leaf diagram Level 2

12 learners' resting heart rates (beats per minute) are: \(71,\ 65,\ 82,\ 74,\ 62,\ 89,\ 78,\ 68,\ 75,\ 80,\ 73,\ 85\). (a) Organise this data using a stem-and-leaf diagram. (b) Use it to find the median. (c) Find the range.

Show solution
  1. 1(a) Each value's TENS digit is the "stem," its UNITS digit is a "leaf." Sort the leaves on each stem in order: \(62,65,68\) on stem 6; \(71,73,74,75,78\) on stem 7; \(80,82,85,89\) on stem 8.
StemLeaves
62  5  8
71  3  4  5  8
80  2  5  9
  1. 2(b) The diagram already has every value in sorted order, stem by stem: \(62,65,68,71,73,74,75,78,80,82,85,89\) — 12 values (even), so average the two middle (6th, 7th) ones: \(\dfrac{74+75}{2}=\boxed{74{,}5}\)
  2. 3(c) Range \(=\) maximum \(-\) minimum \(=89-62=\boxed{27}\)
Why bother with the stems?
A stem-and-leaf diagram keeps every original value (unlike a histogram, which only keeps interval totals) while STILL sorting the data for you as you build it — the perfect middle ground between a raw unsorted list and a grouped-frequency table.
Quick check: central tendency

A class of 9 learners scores: 45, 52, 58, 60, 62, 65, 70, 75, 98 on a test. Which measure of central tendency is most affected by the score of 98?

The mean of 4 numbers is 20. Three of the numbers are 15, 18, 25. What is the fourth number?

Grouped Data — Why and How

When there's too much raw data to list, group it into intervals first.

The trade-off
Grouping 200 individual test marks into 8 intervals makes the data manageable to read — but it throws away the exact values. Once data is grouped, you can no longer calculate the exact mean, only an ESTIMATE, using each interval's MIDPOINT as a stand-in for every value inside it.
Estimated mean

Multiply each interval's midpoint by its frequency, add these products together, then divide by the total frequency \(n\).

Modal interval

The interval with the HIGHEST frequency — you can no longer name one exact modal value, only the interval it falls in.

Median interval

Build a running (cumulative) total of the frequencies; the median interval is the one where the running total first reaches or passes \(\dfrac{n}{2}\).

CAPS convention
Grade 10 grouped intervals are written as inequalities, e.g. \(20\le x<30\), not as "20–29". This makes it unambiguous which interval a boundary value (like exactly 30) belongs to.

Worked Examples — Grouped Data

A small example first, then the exact style CAPS itself uses.

Worked example — ages of 20 people Level 1–2

Estimate the mean age, and state the modal and median intervals, for this grouped data:

Age (years)Frequency
\(10\le x<20\)3
\(20\le x<30\)7
\(30\le x<40\)6
\(40\le x<50\)4
Show solution
  1. 1Total frequency: \(n=3+7+6+4=20\)
  2. 2Midpoints of each interval: \(15,\ 25,\ 35,\ 45\)
  3. 3Estimated mean: \(\dfrac{(15)(3)+(25)(7)+(35)(6)+(45)(4)}{20}=\dfrac{45+175+210+180}{20}=\dfrac{610}{20}=\boxed{30{,}5}\)
  4. 4Modal interval: the highest frequency is 7, in \(\boxed{20\le x<30}\)
  5. 5Cumulative frequency: \(3,\ 10,\ 16,\ 20\). The median is the \(\dfrac{n}{2}=10\)th value; the running total FIRST reaches 10 in the interval \(\boxed{20\le x<30}\)
10 20 30 40 50 7 0 Age (years)
Seeing the bars makes the modal interval obvious at a glance — the tallest bar (\(20\le x<30\)) is exactly the interval with the highest frequency, matching step 4 above. Full histogram construction is a Grade 11 skill; here it's just a picture of the table.
Worked example — the CAPS official style A real CAPS clarification example

The percentage marks of 200 Grade 10 learners are summarised below. (a) Calculate the approximate mean mark. (b) Identify the interval in which the median lies. (c) Identify the interval containing the lower quartile. (d) Identify the interval containing the upper quartile. (e) Identify the interval containing the 30th percentile.

PercentageNumber of candidates
\(0\le x<20\)4
\(20\le x<30\)10
\(30\le x<40\)37
\(40\le x<50\)43
\(50\le x<60\)36
\(60\le x<70\)26
\(70\le x<80\)24
\(80\le x<100\)20
Show solution
  1. 1Check the total: \(4+10+37+43+36+26+24+20=200\)✓ — matches the 200 learners given
  2. 2(a) Midpoints: \(10,25,35,45,55,65,75,90\). Estimated mean \(=\dfrac{10(4)+25(10)+35(37)+45(43)+55(36)+65(26)+75(24)+90(20)}{200}=\dfrac{10790}{200}=\boxed{53{,}95}\)
  3. 3Build the cumulative frequency: \(4,\ 14,\ 51,\ 94,\ 130,\ 156,\ 180,\ 200\)
  4. 4(b) Median position \(=\dfrac{n}{2}=100\)th value. The running total passes 94 and reaches 130 in the NEXT interval: \(\boxed{50\le x<60}\)
  5. 5(c) Lower quartile position \(=\dfrac{n}{4}=50\)th value. Running total passes 14 and reaches 51: \(\boxed{30\le x<40}\)
  6. 6(d) Upper quartile position \(=\dfrac{3n}{4}=150\)th value. Running total passes 130 and reaches 156: \(\boxed{60\le x<70}\)
  7. 7(e) 30th percentile position \(=0{,}30\times200=60\)th value. Running total passes 51 and reaches 94: \(\boxed{40\le x<50}\)
The pattern behind (b)–(e)
Every one of these is the SAME method: turn the target position into a number (n/2 for the median, n/4 for Q1, 3n/4 for Q3, or a percentage of n for a percentile), then find the first interval whose cumulative frequency reaches or passes that number.
Quick check: grouped data

For the interval \(30\le x<40\), what value is used as its "typical" value when estimating the mean?

A grouped data set has cumulative frequencies 5, 18, 40, 55 across four intervals, with n = 55. Which interval contains the median?

Dispersion — How Spread Out Is the Data?

Central tendency alone can hide very different data sets.

Same mean, very different data
Class A: \(48,49,50,51,52\) and Class B: \(10,30,50,70,90\) — both have a mean of exactly 50, but Class B is far more spread out. Measures of dispersion capture exactly this difference, which the mean alone completely misses.
Range

\(\text{Range}=\text{max}-\text{min}\). Simple, but only uses two values — one extreme outlier at either end distorts it completely.

Quartiles (\(Q_1,Q_2,Q_3\))

\(Q_2\) is the median. \(Q_1\) is the median of the lower half of the data; \(Q_3\) is the median of the upper half (excluding \(Q_2\) itself if \(n\) is odd).

Interquartile range (IQR)

\(\text{IQR}=Q_3-Q_1\) — the spread of the MIDDLE 50% of the data, ignoring extreme values at either end.

Semi-interquartile range

\(\dfrac{Q_3-Q_1}{2}\) — half the IQR, sometimes used as a single "typical spread from the median" figure.

Worked Examples — Range, Quartiles, IQR

Odd and even data sets need slightly different care when splitting into halves.

Worked example — odd number of values Level 2

Find the range, \(Q_1\), \(Q_2\), \(Q_3\), the IQR and the semi-IQR of: \(9,\ 5,\ 13,\ 2,\ 11,\ 15,\ 7,\ 8,\ 4\)

Show solution
  1. 1Arrange in order: \(2,4,5,7,8,9,11,13,15\) — 9 values
  2. 2Range \(=15-2=\boxed{13}\)
  3. 3Median (\(Q_2\)): the middle (5th) value \(=\boxed{8}\)
  4. 4Lower half (excluding the median itself): \(2,4,5,7\). \(Q_1\) is its median, the average of the two middle values: \(\dfrac{4+5}{2}=\boxed{4{,}5}\)
  5. 5Upper half: \(9,11,13,15\). \(Q_3\) is its median: \(\dfrac{11+13}{2}=\boxed{12}\)
  6. 6IQR \(=Q_3-Q_1=12-4{,}5=\boxed{7{,}5}\); semi-IQR \(=\dfrac{7{,}5}{2}=\boxed{3{,}75}\)
Worked example — even number of values Level 3

Find the range, \(Q_1\), \(Q_2\), \(Q_3\) and the IQR of: \(31,\ 25,\ 38,\ 47,\ 23,\ 33,\ 44,\ 28,\ 40,\ 35\)

Show solution
  1. 1Arrange in order: \(23,25,28,31,33,35,38,40,44,47\) — 10 values (even)
  2. 2Range \(=47-23=\boxed{24}\)
  3. 3With an even count, the whole data set splits cleanly in half: lower half \(23,25,28,31,33\), upper half \(35,38,40,44,47\)
  4. 4Median (\(Q_2\)): average of the two middle values (5th, 6th): \(\dfrac{33+35}{2}=\boxed{34}\)
  5. 5\(Q_1\) = median of the lower half \(\{23,25,28,31,33\}=\boxed{28}\); \(Q_3\) = median of the upper half \(\{35,38,40,44,47\}=\boxed{40}\)
  6. 6IQR \(=40-28=\boxed{12}\)
Odd vs. even, side by side
Odd count: the median is an actual data value, and it is EXCLUDED from both halves before finding \(Q_1\)/\(Q_3\). Even count: the median falls between two values, so the whole data set is used for both halves — nothing needs to be excluded.
Quick check: dispersion

Why is the range considered a "weak" measure of spread compared to the IQR?

For the data set 6, 10, 14, 18, 22, 26 (n = 6, even), what is Q1?

The Five-Number Summary and Box-and-Whisker Diagram

One picture, five numbers, the whole shape of the data.

The five numbers

Minimum, \(Q_1\), median (\(Q_2\)), \(Q_3\), maximum — exactly the values you already know how to find.

Drawing the diagram
  • Draw a number line covering the full range of the data.
  • Draw a box from \(Q_1\) to \(Q_3\), with a line inside it at the median.
  • Draw a "whisker" line from each end of the box out to the minimum and maximum.
12 18 25 33 40 min Q1 median Q3 max
The box covers the middle 50% of the data (\(Q_1\) to \(Q_3\)); the whiskers reach out to the full minimum and maximum.
Reading the shape
A long whisker or wide box section on one side means that part of the data is more spread out. If the median line sits off-centre inside the box, the data is skewed toward the side with the shorter distance.

Worked Examples — Building and Reading a Box Plot

Drawing one from data, then reading one that's already drawn.

Worked example — find the five-number summary Level 2

Find the five-number summary for: \(20,\ 15,\ 33,\ 12,\ 28,\ 40,\ 18,\ 22,\ 25,\ 30,\ 36\)

Show solution
  1. 1Arrange in order: \(12,15,18,20,22,25,28,30,33,36,40\) — 11 values
  2. 2Minimum \(=\boxed{12}\), maximum \(=\boxed{40}\)
  3. 3Median (6th value) \(=\boxed{25}\)
  4. 4Lower half: \(12,15,18,20,22\). \(Q_1\) (its middle value) \(=\boxed{18}\)
  5. 5Upper half: \(28,30,33,36,40\). \(Q_3\) (its middle value) \(=\boxed{33}\)
  6. 6Five-number summary: \(\boxed{12,\ 18,\ 25,\ 33,\ 40}\) — exactly the box plot shown on the previous slide
Worked example — read a given box plot Level 3

A box-and-whisker plot for a set of test scores has minimum 40, \(Q_1=55\), median 68, \(Q_3=78\), maximum 92. (a) What percentage of learners scored below 55? (b) What is the IQR? (c) Is the data skewed, and if so, in which direction?

Show solution
  1. 1(a) \(Q_1\) is, by definition, the value below which 25% of the data lies: \(\boxed{25\%}\)
  2. 2(b) IQR \(=Q_3-Q_1=78-55=\boxed{23}\)
  3. 3(c) Compare the two halves: min to median spans \(68-40=28\); median to max spans \(92-68=24\). The lower half is slightly more spread out, so the data is mildly skewed toward the LOWER scores — a few learners scored much further below the median than any learner scored above it
40 55 68 78 92 min Q1 median Q3 max
The exact box plot this worked example describes — notice the box's own lower half (Q1 to median) is visibly wider than its upper half (median to Q3), matching part (c)'s conclusion.
Worked example — a strongly skewed plot Level 3

A box-and-whisker plot for household incomes has minimum 20, \(Q_1=28\), median 33, \(Q_3=42\), maximum 75 (in R thousands). Describe the shape of this data.

Show solution
  1. 1Min to median spans \(33-20=13\); median to max spans \(75-33=42\) — the UPPER half is more than three times as spread out as the lower half.
  2. 2\(\boxed{\text{The data is strongly skewed toward the HIGH incomes}}\) — most households earn a similar, modest amount, but a small number of very high earners stretch the upper whisker far to the right.
20 28 33 42 75 min median max
The long right whisker is the visual signature of high-income (right) skew — a shape you will see constantly in real income, house-price and wealth data.
Recognise it when...
Any question giving you five key values (or a drawn box plot) directly — without a raw data list — is a "read the box plot" question. You never need to recompute anything; just reason from the five values already given.
Quick check: box-and-whisker

In a box-and-whisker diagram, what does the BOX itself (not the whiskers) represent?

A box plot has min=10, Q1=20, median=30, Q3=32, max=35. What does the short distance between the median and Q3 suggest?

Using Summaries to Compare Two Data Sets

This is the actual exam skill CAPS names: use the numbers AND the picture to say something true.

Worked example — same mean, different spread Level 1–2

Set A: \(12,13,14,15,16\). Set B: \(6,10,14,18,22\). Compare the two sets.

Show solution
  1. 1Set A mean \(=\dfrac{12+13+14+15+16}{5}=\dfrac{70}{5}=14\); range \(=16-12=4\)
  2. 2Set B mean \(=\dfrac{6+10+14+18+22}{5}=\dfrac{70}{5}=14\); range \(=22-6=16\)
  3. 3\(\boxed{\text{Both sets share the exact same mean (14), but Set B is four times more spread out}}\) — the mean alone completely hides this difference, which is exactly why a measure of spread always needs to be reported alongside it.
Worked example — comparing two classes Level 4

Two Grade 10 classes wrote the same test (out of 100). Class A: \(45,52,58,61,63,65,68,70,72,75,80\). Class B: \(40,48,55,60,64,68,71,74,78,85,92\). Compare the two classes' performance.

Show solution
  1. 1Class A (11 values, already ordered): mean \(=\dfrac{45+52+\cdots+80}{11}\approx64{,}45\); five-number summary \(45,58,65,72,80\)
  2. 2Class B (11 values, already ordered): mean \(\approx66{,}82\); five-number summary \(40,55,68,78,92\)
  3. 3Compare central tendency: Class B's mean (\(66{,}82\)) and median (\(68\)) are both slightly higher than Class A's (\(64{,}45\) and \(65\)) — Class B did marginally better on average
  4. 4Compare spread: Class A's range \(=80-45=35\) and IQR \(=72-58=14\). Class B's range \(=92-40=52\) and IQR \(=78-55=23\) — Class B is considerably MORE spread out on both measures
  5. 5\(\boxed{\text{Class B scored slightly higher on average, but with far more variability}}\) — Class A's results were more tightly clustered around its own mean
A B 40 50 60 70 80 90
Stacked on the same scale, Class B's box and whiskers are visibly wider than Class A's — confirming numerically what the IQR and range already showed.
The exam skill
A "compare" question is never finished after just stating numbers. Always translate the numbers into a plain-language conclusion: WHO scored higher on average, and WHOSE results were more consistent.

Grade 10 Mastery Sprint

Work first. Open one answer only when your own line of working is complete.

01 — Mean, median, mode

Data: \(6,9,9,12,14\). Answer: mean \(=10\), median \(=9\), mode \(=9\).

02 — Modal interval

Frequencies \(5,12,8,3\) across 4 intervals. Answer: the 2nd interval (frequency 12, the highest).

03 — IQR

\(Q_1=14,\ Q_3=26\). Answer: \(\text{IQR}=26-14=12\).

04 — Box plot shape

Median sits much closer to \(Q_1\) than to \(Q_3\). Answer: the upper half of the data is more spread out.

Exam Strategy

Calculate mean, median and mode of ungrouped data, including "find the missing value" problems.
Estimate the mean of grouped data using midpoints, and identify the modal and median intervals.
Find quartiles correctly for BOTH odd and even data sets, then compute the range, IQR and semi-IQR.
Find the five-number summary and draw (or read) a box-and-whisker diagram.
Turn the numbers into a plain-language comparison, not just a list of values.
Avoid this

Forgetting to sort the data before finding the median or quartiles.

Including the median itself in the lower/upper half when \(n\) is odd.

Stopping at the numbers without stating what they mean in context.

Do this

Always write the sorted list out first — it's the single most common lost mark.

Double-check: does your \(n\) for the lower/upper half match what you expect?

End every "compare" answer with a sentence in words.

More explanation and exercises:Siyavula Grade 10 Statistics
Summary complete

You now have the toolkit.

Use the Mastery Bank to build fluency. Then take the test without notes and use the result to choose the exact slide to revisit.

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Learn It in Short Videos

Four free, independent videos — not made by Equation Station SA.

Mean, Median and Mode

The three measures of central tendency, from scratch.

Khan Academy · Statistics intro: Mean, median, and mode

Mean of Grouped Data

Using midpoints to estimate the mean of a frequency table.

Khan Academy · Finding mean of the grouped data with frequency

Interquartile Range

Finding Q1, Q3 and the IQR step by step.

Khan Academy · How to calculate interquartile range IQR

Box-and-Whisker Plot

Building the five-number summary into a diagram.

Khan Academy · Box and whisker plot

Practise in the right order

The core teaching is above. These are the next steps, not a replacement for it.

01
Built-in practice
Statistics Mastery Bank

18 questions by skill, with concise reveal answers and methods.

Start after the slides
Open Mastery Bank
02
Built-in check
Test Your Knowledge

Use the short exam-style self-check when you want a fast confidence check.

Then target one weak skill
Take the Test
CAPS
Free textbook chapter
Siyavula: Grade 10 Statistics

Use its own worked examples for extra explanation and exercises.

Free • CAPS aligned
Open Siyavula
DBE
Official free books
DBE Grade 10 Textbooks

Official state-owned learner books and teacher support for Grade 10 Mathematics.

Official • free access
Open DBE Books

Frequently Asked Questions

Short answers for the checks learners make while preparing for the Grade 10 CAPS exam.

What does CAPS require for Grade 10 Statistics?

Revise measures of central tendency in ungrouped data; calculate an estimated mean, modal interval and median interval for grouped data; revise range and extend it to percentiles, quartiles, the interquartile range and semi-interquartile range; find the five-number summary and draw a box-and-whisker diagram; and use these summaries with graphs to comment meaningfully on data in context.

Why do we only get an ESTIMATE of the mean for grouped data?

Once data is grouped into intervals, the individual values are lost — you only know how many values fell inside each interval, not their exact values. Using the midpoint of each interval as a stand-in for every value inside it gives a good estimate, not the exact original mean.

Is variance and standard deviation part of Grade 10?

No. Variance and standard deviation are introduced in Grade 11, alongside histograms, frequency polygons and ogives. Grade 10 Statistics covers central tendency, grouped-data estimates, quartiles and the box-and-whisker diagram.

How do you find quartiles by hand?

Arrange the data in order and find the median, which splits it into a lower half and an upper half (excluding the median itself if there is an odd number of values). Q1 is the median of the lower half; Q3 is the median of the upper half.

Where should I practise next?

Finish the interactive slides, open the Mastery Bank, then take the short self-test without notes.